Answer:
[tex]\large \boxed{\text{1.76 m}}[/tex]
Explanation:
Data:
Lifetime = 2.55 × 10⁻⁸ s
Speed = 0.230c
Calculations:
[tex]\text{Speed} = \text{0.230c} = 0.230 \times \dfrac{\text{2.998 $\times 10^{8}$ m}}{\text{1 s}} = 6.895 \times 10^{7}\text{ m/s }\\\\\begin{array}{rcl}\text{Distance} & = & \text{speed $\times$ time}\\& = & \dfrac{6.895 \times 10^{7}\text { m}}{\text{1 s}} \times 2.55 \times 10^{-8}\text{ s}\\\\& = & \textbf{1.76 m}\\\end{array}\\\text{The pion travels $\large \boxed{\textbf{1.76 m}}$ in its lifetime.}[/tex]