Answer:
0.5050
Step-by-step explanation:
Given that in a recent school election at a large school we know that 45% of the students supported candidate X and the other 55% supported candidate Y.
We know that each candidate is independent of other
Hence prob for supporting X = 0.45 for each student and y = 0.55
We select 2 students at random
The prob that they both supported the same candidate
=Prob both supported X or prob both supported Y
=prob both supported X + prob both supported Y(since mutually exclusive)
=[tex](0.45)^2 +(0.55)^2\\=0.2025+0.3025\\=0.5050[/tex]
