Answer:
(a) 5000 N
(b) 0.25 cm
Explanation:
(a)
Tensile strength is given by [tex]\frac {F}{A}[/tex] where F is force and A is area
F=Area* Tensile strength
[tex]F=100*10^{6}*50*10^{-6}=5000 N[/tex]
Therefore, F=5000 N
(b)
Young’s modulus, [tex]E=\frac {stress}{strain}[/tex]
[tex]Strain=\frac {\triangle l}{l}[/tex] where [tex]\triangle l[/tex] is elongation and l is original length
[tex]\triangle l=\frac {100*10^{6}*40*10^{-2}}{1.6*10^{10}=2.5*10^{-4} m[/tex]
[tex]\triangle l=0.25 cm[/tex]