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5.5 kg of liquid water initially at 12°C is to be heated to 95°C in a teapot equipped with an 800-W electric heating element inside. The specific heat of water can be taken to be 4.18 kJ/kg·°C, and the heat loss from the water during heating can be neglected. The time it takes to heat water to the desired temperature is ____ min.

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cjrodriguez89

Answer: 39 min 45 sec.

Explanation:

Empirically, it has been found that the thermal energy needed to raise the temperature of a solid, using only conduction, can be written as follows:

Q = c m ΔT

Power, by definition, is energy delivered in some time t, so we can put the following:

Q = Pt = c m Δt ⇒ t = c m Δt / P

Replacing by the values, we get;

t = 4180 J/kg.ºC . 5.5 Kg. (95º - 12º) / 800 W = 2385 sec.

Converting to minutes, we have t= 39.75 min = 39 min 45 sec.