Answer:
The older repear will harvest in 6 hrs
Explanation:
Given a field can be harvested in 1 hr with 2 reapers
Consider the total field to be 1
Let x be the time of older’s reaper
The field can be harvested in 1.2 hr with newer reaper alone
Older’s time of harvesting = [tex]\frac{1}{x}[/tex] per hour
Newer’s time of harvesting = [tex]\frac{1}{1.2}[/tex]per hour
Total (Older+Newer) = 1 = [tex]{\frac{1}{x}+\frac{1}{1.2}[/tex]}
[tex]\frac{1}{x}+\frac{1}{1.2}=1[/tex]
[tex]\frac{1.2+x}{1.2 x}=1[/tex]
1.2 + x = 1.2x
1.2 = 0.2x
x = 6
Therefore, older repear will harvest in 6 hrs
