Answer:
[tex]3.09\times 10^{9}\ K[/tex]
Explanation:
K = Kinetic energy of the fusion experiment = [tex]6.40\times 10^{-14}\ J[/tex]
k = Boltzmann constant = [tex]1.38\times 10^{-23}\ J/K[/tex]
T = Temperature of gas
Kinetic energy of a gas molecule is given by
[tex]K=\frac{3}{2}kT\\\Rightarrow T=\frac{2K}{3k}\\\Rightarrow t=\frac{2\times 6.40\times 10^{-14}}{3\times 1.38\times 10^{-23}}\\\Rightarrow T=3091787439.61352=3.09\times 10^{9}\ K[/tex]
The temperature which is needed is [tex]3.09\times 10^{9}\ K[/tex]