Answer:
9.17 feet.
Step-by-step explanation:
See the diagram attached to this answer.
Let, AB is the pole and CD is the tree.
From the top of the pole to the base of the tree the angle of depression as per the condition is 63°.
So, ∠ EBC = ∠ ACB = 63° {Since, BE ║ AC}
So, from Δ ABC, [tex]\tan 63 = \frac{AB}{AC} = \frac{18}{AC}[/tex] {Given height of the tower AB = 18 feet}
⇒ [tex]AC = \frac{18}{\tan 63} = 9.17[/tex] feet.
Therefore, the distance between the pole and the tree is 9.17 feet. (Answer)
