Answer:
0.7477
Step-by-step explanation:
The mean(X) = 25,000 hrs
Standard deviation (σ) = 1500 hrs
The probability that the light bulb lasts more than 24,000hrs is Pr (X˃24,000)
Using Z-scores, Z= (X- μ)/σ
For X = 24,000
Z = (24,000 – 25,000)/1500
Z = -1000/1500
Z = -0.667
From the normal distribution table, Z= 0.667 = 0.2477
Φ(Z) = 0.2477
Recall that if Z is negative,
Pr (X˃a) = 0.5 + Φ(Z)
Pr (X˃24,000) = 0.5 + 0.2477
= 0.7477