Answer:
3(x−1)(x+5)/(2x(x−5))
Step-by-step explanation:
In general simplifying something like this requires you factor the various polynomials to see what factors may cancel.
[tex]\dfrac{2x^2+2x-40}{4x^2-12x-16}\cdot\dfrac{3x^2-3}{x^2-5x}=\dfrac{2(x-4)(x+5)\cdot 3(x-1)(x+1)}{4(x-4)(x+1)\cdot x(x-5)}\\\\=\dfrac{3(x-1)(x+5)}{2x(x-5)}[/tex]