For this case we have the following equation:
[tex]3x-6y = 12[/tex]
We must solve the equation for the variable "y":
Subtracting 3x from both sides of the equation we have:
[tex]-6y = 12-3x[/tex]
Dividing by 6 to both sides of the equation:
[tex]-y = \frac {12} {6} - \frac {3x} {6}\\-y = 2- \frac {x} {2}[/tex]
We multiply by -1 on both sides of the equation:
[tex]y = \frac {x} {2} -2[/tex]
Answer:
[tex]y = \frac {x} {2} -2[/tex]
