Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.
Solution:
Need to calculate [tex]\sqrt[3]{1728}[/tex] and then multiply the result by [tex]\sqrt[3]{14903}[/tex]
Let us first evaluate [tex]\sqrt[3]{1728}[/tex]
[tex]\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12[/tex]
As need to multiply 12 by [tex]\sqrt[3]{14903}[/tex]
[tex]\Rightarrow 12 \times \sqrt[3]{14903}[/tex]
On solving [tex]\sqrt[3]{14903}[/tex], we get
[tex]\sqrt[3]{14903}=24.608[/tex]
[tex]\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306[/tex]
Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.
