Answer:
x = 7.14 meters
Explanation:
It is given that,
Current in wire 1, [tex]I_1=2\ A[/tex]
Current in wire 2, [tex]I_2=5\ A[/tex]
Distance between parallel wires, r = 25 cm
Let at P point the net magnetic field equal to 0. The magnetic field at a point midway between the is given by :
[tex]B=\dfrac{\mu_oI}{2\pi r}[/tex]
Let the distance is x from wire 1. So,
[tex]\dfrac{I_1}{r}=\dfrac{I_2}{(0.25-r)}[/tex]
[tex]\dfrac{2}{r}=\dfrac{5}{(25-r)}[/tex]
[tex]x=\dfrac{50}{7}\ m[/tex]
x = 7.14 meters
So, the magnetic field will be 0 at a distance of 7.14 meters from wire 1. Hence, this is the required solution.
