The tension in the rope is 40 N
Explanation:
For an object in uniform circular motion, the centripetal force is given by
[tex]F=m\frac{v^2}{r}[/tex]
where
m is the mass of the object
v is its velocity
r is the radius of the circular path
In this problem, the tension in the rope is providing the centripetal force, so we can write
[tex]T=m\frac{v^2}{r}[/tex]
where we have:
T = tension in the rope
m = 5 kg mass of the ball
r = 2 m radius of the circle
v = 4 m/s is the velocity
Substituting, we find the tension:
[tex]T=(5)\frac{4^2}{2}=40 N[/tex]
Learn more about circular motion:
brainly.com/question/2562955
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