Answer:
KE=2.3 x 10⁻¹⁹ J
Explanation:
Given that
λ = 544 nm
λ' = 485 nm
The kinetic energy KE given as
KE= E - Ф
Where
[tex]E=\dfrac{hC}{\lambda'}[/tex]
[tex]\phi=\dfrac{hC}{\lambda}[/tex]
h= 6.626 x 10⁻³⁴
C=3 x 10⁸ m/s
Now by putting the values
[tex]KE=\dfrac{hC}{\lambda'}-\dfrac{hC}{\lambda}[/tex]
[tex]KE=\dfrac{34.34\times 10^{-34}\times 3\times 10^8}{485\times 10^{-9}}- \dfrac{34.34\times 10^{-34}\times 3\times 10^8}{544\times 10^{-9}}[/tex]
KE=2.3 x 10⁻¹⁹ J
This is kinetic energy.
