Answer:
a.[tex]Cp=0.523[/tex]
b.[tex]Cp=25.02\frac{J}{mol^\circ C}[/tex]
Explanation:
a. First, we solve the specific heat equation as follows:
[tex]Q=mCp\Delta T\\Cp=\frac{Q}{m\Delta T}\\Cp=\frac{89.7J}{33.0g\times5.20^\circ C}=0.523[/tex]
b. Then, we use the molar mass of titanium to determine its molar heat capacity, as follows:
[tex]Cp=0.523\frac{J}{g^\circ C}\times 47.87\frac{g}{mol}\\Cp=25.02\frac{J}{mol^\circ C}[/tex]
