Answer:
The image distance is 20.0 cm.
Explanation:
Given that,
Power = 1.55 dp
Distance between book to eye = 26.0+3.00=29.0 cm
We need to calculate the focal length
Using formula of focal length
[tex]f = \dfrac{1}{P}[/tex]
Put the value into the formula
[tex]f=\dfrac{1}{1.55}[/tex]
[tex]f=0.645\ m[/tex]
[tex]f=64.5\ cm[/tex]
We need to calculate the image distance
Using lens formula
[tex]\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}[/tex]
[tex]\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{-u}[/tex]
Put the value into the formula
[tex]\dfrac{1}{v}=\dfrac{1}{64.5}-\dfrac{1}{-29}[/tex]
[tex]\dfrac{1}{v}=\dfrac{187}{3741}[/tex]
[tex]v=20.0\ cm[/tex]
Hence, The image distance is 20.0 cm.
