Answer:
[tex]L = 0.018 kg m^2/s[/tex]
Explanation:
Angular speed and linear speed is related to each other as
[tex]v = R\omega[/tex]
here we know that
[tex]v = 0.50 m/s[/tex]
[tex]R = 0.08 m[/tex]
now we have
[tex]\omega = \frac{v}{R}[/tex]
[tex]\omega = \frac{0.50}{0.08}[/tex]
[tex]\omega = 6.25 rad/s[/tex]
Now we know that moment of inertia of the system is given as
[tex]I = (2M + m)R^2 [tex]
[tex]I = (2\times 0.22 + 0.0045)(0.08)^2[/tex]
[tex]I = 2.84 \times 10^{-3} kg m^2[/tex]
Now angular momentum of the system is given as
[tex]L = I\omega [/tex]
[tex]L = (2.84 \times 10^{-3})(6.25)[/tex]
[tex]L = 0.018 kg m^2/s[/tex]
