Answer: The probability that the next roll is also a 6 is 88.10%.
Step-by-step explanation:
Since we have given that
There are 2 dices :
1) Standard dice
2) Biased dice
Probability of getting a standard dice = [tex]\dfrac{1}{2}=0.5[/tex]
Probability of getting a biased dice = [tex]\dfrac{1}{2}=0.5[/tex]
Probability of getting 6 from standard dice = P(6|S) = [tex]\dfrac{1}{6}[/tex]
Probability of getting 6 from biased dice = P(6|B)=1
We need to find the probability that the next roll is also a 6.
so, our probability becomes,
[tex]P(S|6)=\dfrac{P(6|S)\times P(S)}{P(6)}=\dfrac{\dfrac{1}{6}\times 0.5}{\dfrac{1}{6}\times 0.5+1\times 0.5}=\dfrac{1}{7}[/tex]
So, the required probability would be
[tex]\dfrac{1}{7}\times \dfrac{1}{6}+1\times \dfrac{6}{7}\\\\\\\\=0.8810\\\\=88.10\%[/tex]
Hence, the probability that the next roll is also a 6 is 88.10%.