if a gas sample has a pressure of 761 mmhg at 0.00°c by how much does the temperature have to decrease to lower the pressure to 759 mmhg?​

Respuesta :

Answer:

272.43 K or -0.718°C

Explanation:

We are given;

The initial pressure,P1 as 761 mmHg

Initial temperature, T1 as 0.00°C which is equivalent to 273.15 K

Final pressure as 759 mmHg

We are required to calculate the final temperature;

According to pressure law, the pressure of a gas and absolute temperature are directly proportional at constant volume.

That is; Pα T

Therefore, at varying pressure and temperature,

[tex]\frac{P1}{T1}=\frac{P2}{T2}[/tex]

To get final temperature;

[tex]T2=\frac{P2T1}{P1}[/tex]

[tex]T2=\frac{(759 mmHg)(273.15K)}{761 mmHg}[/tex]

[tex]T2=272.43K[/tex]

Therefore, the final temperature will be 272.43 K or -0.718°C