Answer:
The value of sec O is [tex]\frac{10}{9}[/tex]
Step-by-step explanation:
Given as for right angle triangle
cos O = [tex]\frac{9}{10}[/tex]
Now from Pythagoras theorem, for right angled triangle
H² = P² + B²
∵ cos O = [tex]\frac{9}{10}[/tex] = [tex]\frac{Base}{hypotenuse}[/tex]
So Perpendicular² = Hypotenuse² - Base²
Or, Perpendicular² = 10² - 9²
Or, Perpendicular² = 100 - 81 = 19
∴ Perpendicular ( P ) = [tex]\sqrt{19}[/tex]
∵ , Sec Ф = [tex]\frac{hypotenuse}{base}[/tex]
So , Sec O = [tex]\frac{10}{9}[/tex]
Hence The value of sec O is [tex]\frac{10}{9}[/tex] Answer
