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What is the final velocity of a rocket that is traveling at 205 m/s and accelerates at
8.03 m/s2 while moving 1750 m?

Respuesta :

MathPhys

Answer:

70,100 m/s

Explanation:

Given:

v₀ = 205 m/s

a = 8.03 m/s²

Δx = 1750 m

Find: v

v² = v₀² + 2aΔx

v² = (205 m/s)² + 2 (8.03 m/s²) (1750 m)

v = 70,130 m/s

Rounding to three significant figures, the final velocity is 70,100 m/s.

Answer:

70.100m/s

Explanation:

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