1. Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer than 40°F is an unsafe food practice. Which of the inequalities below represent the union of these improper storage temperatures, t, in degrees Fahrenheit? A. T > 35 or t <40 B. T < 35 or t >40 C. T > 35 AND t < 40 D. T < 35 AND t > 40 2. What are the solution(s) to the absolute value equation below? 15| x-7|+4=10|x-7|+4 A. X= - 5\7 or x = 5\7 B. X=5 or x= -5 C. Only x=7 D. X= 7/5 or x= -7\5 3. Match the absolute value equation with the statement that describes the solutions to that equation. A. Two solutions B. Solution C. No solution |x+1|+5=2 |4x+12|=0 |3x|=9

Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer than 40°F is an unsafe food practice.

The union is written as A∪B or “A or B”.

The intersection of two sets is written as A∩B or “A and B”

We need to determine the inequalities represent the union of these improper storage.

That means we will use A∪B or “A or B”.

The improper storage temperatures is when temperature is less than 35°F or greater than 40°F.

Hence, the required inequality is T < 35 or t >40.

Part (B) 15| x-7|+4=10|x-7|+4

Solve the inequality as shown below:

Subtract 4 from both sides.

[tex]15| x-7|+4-4=10|x-7|+4-4[/tex]

Subtract 10|x-7| from both sides

[tex]5\left|x-7\right|=0\\\left|x-7\right|=0\\x=7[/tex]

Hence, the correct option is C) Only x=7.

Part (C) Match the solution,

[tex]\left|x+1\right|+5=2[/tex]

Subtract 2 from both sides.

[tex]\left|x+1\right|=-3[/tex]

Absolute value cannot be less than 0.

Hence, |x+1|+5=2 has no solution.

[tex]|4x+12|=0[/tex]

[tex]4x+12=0[/tex]

[tex]x=-3[/tex]

Hence, |4x+12|=0 has one solution.

[tex]|3x|=9[/tex]

[tex]\mathrm{If}\:|u|\:=\:a,\:a>0\:\mathrm{then}\:u\:=\:a\:\quad \mathrm{or}\quad \:u\:=\:-a[/tex]

[tex]3x=-9\quad \mathrm{or}\quad \:3x=9\\x=-3\quad \mathrm{or}\quad \:x=3[/tex]

Hence, |3x|=9 has two solution.