Two regular six-sided dice are tossed. Compute the probability that the sum of the pips on the upward faces of the two dice is the following. (See the figure below for the sample space of this experiment. Enter the probability as a fraction.) At most 5

The first die has 6 possible outcomes. For each outcome there are 6 possible outcomes for the second die. So the total number of combinations is 6×6 = 36.

The possible combinations that are at most 5:

1 and 4, 2 and 3, 3 and 2, 4 and 1

So the probability is 4/36 = 1/9.

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adioabiola adioabiola · Answer 2 · 2022-01-03T13:02:19+01:00

The probability that the sum of the pips on the upward faces of the two dice is at most 5 is; 5/18

The total number of possible outcomes of the two six-sided dice is 36.

The possible outcomes for the sum of the pips on the upward faces of the two dice to be at most 5 are as follows;

(1,4), (4,1), (2,3), (3,2), (3, 1), (1,3), (2,2), (1,2), (2,1), (1,1)

Therefore, we have 10 possible outcomes.

The probability that the sum of the pips on the upward faces of the two dice is at most 5 is therefore;

P = 10/36

P = 5/18.