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Assume the average fuel flow rate at the peak torque speed (1500 rpm) is 15kg/hr for a sixcylinder four-stroke diesel engine under a certain condition. Each cylinder has one injector and each injector has 6 nozzle holes with a diameter of 200 micrometer. The discharge coefficient of the injector nozzle is 0.75. If the fuel injection pressure difference across the injector nozzle is 100MPa, what will be the fuel injection duration in Crank Angle degrees? Fuel density is 800 kg/m3 .

Respuesta :

Answer:

Q = 8.845 DEGREE

Explanation:

given data:

combine Mass for 6 cylinder (M) =15 Kg/hr

mass of  each cylinder (m) = 15/6 = 2.5 Kg/hr = 0.000694 Kg/ sec

Engine speed (N)= 1500rpm

Diameter of one nozzle hole ( d) = 200 micrometer = 0.0002 m

Discharge Coefficient (Cd) = 0.75

Pressure difference = 100 MPa

Density of fuel = 800 kg/m^3

velocity of fuel is [tex]v  = cd\sqrt{\frac{2*P}{p}}[/tex]

[tex]v = 0.75 \sqrt{\frac{2\times 100\times 10^6}{800}} = 375 m/sec[/tex]

injected fuel volume  (V) =Area of given  Orifices × Fuel velocity × time of single injection × no of injection/sec

we know that p = m/ V

So[tex] V = \frac{0.000694}{800} =8.68\times10^{-7} m3/sec[/tex]

putting these value in volume equation and solve for Discharge [tex]8.68\times 10^{-7} = (\frac{(3.14}{4})\times 6\times( .0002\times .0002) \times  375 \times  \frac{(Q}{360}) \times \frac{30}{750} \times \frac{(750}{60)}[/tex]

Q = 8.845 DEGREE

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