Answer:
The numbers are 23 and 7
Step-by-step explanation:
1. Set up the equations
Let x = the greater number
and y = the smaller number. Then
(1) x - y = 16
4y = 4 times the smaller number and
4y - 5 = 5 less than 4 times the smaller number. Then
(2) x = 4y - 5
You have a system of two equations:
[tex]\begin{cases}(1) & x - y = 16\\(2) & x = 4y - 5\end{cases}[/tex]
2. Solve the equations
[tex]\begin{array}{lrcll}(3) & 4y - 5 - y & = & 16 &\text{Substituted (2) into (1)}\\& 3y - 5 & = & 16 &\text{Simplified}\\ & 3y & = & 21 &\text{Added 5 to each side}\\(4) &y & = & \mathbf{7} &\text{Divided each side by 3} \\& x - 7 & = & 16 & \text{Substituted (4) into (1)}\\& x& = & \mathbf{23} & \text{Added 7 to each side}\\\end{array}[/tex]
The larger number is 23; the smaller number is 7.
3. Check
[tex]\begin{array}{rclcrcl}23 - 7& = & 16 & \qquad &23&=&4(7) - 5\\16 & = & 16 & \qquad &23& = &28 - 5\\&&& \qquad &23& = &23\\\end{array}[/tex]
OK.
