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Two slits are illuminated by a 348 nm light. The angle between the zeroth-order bright band at the center of the screen and the fourth-order bright band is 13.5 ◦ . If the screen is 154 cm from the double-slit, how far apart is this bright band from the central peak? Answer in cm.

Respuesta :

Answer:0.369 m

Step-by-step explanation:

Given

Distance between slit and screen is [tex]D=154 cm[/tex]

Wavelength [tex]\lambda =348 nm[/tex]

Angle between zeroth order bright fringe and Fourth-order bright fringe is [tex]\theta =13.5^{\circ}[/tex]

let distance between the slits be d

Distance of n th bright fringe From central Fringe is given by

[tex]y_n=\frac{nD\lambda }{d}[/tex]

Also [tex]\tan \theta =\frac{y_4}{D}[/tex]

[tex]y_4=\tan (13.5)\cdot 1.54[/tex]

[tex]y_4=0.24\times 1.54[/tex]

[tex]y_4=0.369 m[/tex]

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