Answer:
P ( percentage of days in which the circulation pass 1,801,000)
is equal to 100 % (almost)
P (percentage of days when the circulation drops below 1,611, 000)
is equal to 0 % (almost)
Step-by-step explanation:
Let, in recent years, the daily circulation of the Wall Street Journal is given by the random variable X.
Then, according to the question,
X [tex]\sim [/tex] Normal (2,276,207 , 70,940)
let,
[tex]\frac{X- 2,276,207}{70940}[/tex] = Z
then Z [tex]\sim [/tex] Normal (0 , 1)
Now , for X = 1,801,000 , Z = [tex]\frac{1,801,000- 2,276,207}{70940}[/tex]
= -6.7 (approx)
Now, P ( percentage of days in which the circulation pass 1,801,000)
= P( Z > -6.7) = 100 % (almost)
So, P (percentage of days when the circulation drops below 1,611, 000)
= 0 % (almost) [ since, 1,801,000 > 1,611,000]