Answer
mass of the block = 0.2 Kg
it stretches the spring from its original length of 0.050 m to 0.060 m.
total length = 0.1 m
FOR , VERTICAL SYSTEM:
K Δx = mg , Δx = 0.01 m
[tex]k = \dfrac{mg}{\Delta x}[/tex]
[tex]k = \dfrac{0.2 \times 9.8}{0.01}[/tex]
k =196 N/m
[tex]\omega = \sqrt{\dfrac{k}{m}}[/tex]
[tex]\omega = \sqrt{\dfrac{196}{0.2}}[/tex]
[tex]\omega = 31.305\ rad/s[/tex]
[tex]f = \dfrac{\omega}{2\pi}[/tex]
[tex]f = \dfrac{31.305}{2\pi}[/tex]
f = 4.98 Hz
for horizontal system
k Δ x = ma
[tex]a = \dfrac{k \Delta x}{m}[/tex]
[tex]a = \dfrac{196\times (0.1-0.05)}{0.2}[/tex]
[tex]a = \dfrac{196\times 0.05}{0.2}[/tex]
a = 49 m/s²
