Answer:[tex]d=\frac{v^2}{8a}[/tex]
Explanation:
Given
winning car accelerates with a and its final velocity is v
considering they both start from rest
time taken by winning car is
v=u+at
where u=initial velocity
a=acceleration
t=time
[tex]v=at[/tex]
[tex]t=\frac{v}{a}[/tex]
Now loosing car is accelerating with [tex]\frac{a}{4}[/tex]
Distance traveled by loosing car in time t
[tex]s_1=ut+\frac{at^2}{2\cdot 4}[/tex]
[tex]s_1=0+\frac{a}{8}\times (\frac{v}{a})^2[/tex]
[tex]s_1=\frac{v^2}{8a}[/tex]
Thus distance d traveled by loosing car is given by [tex]d=\frac{v^2}{8a}[/tex]
