Respuesta :
Answer:
B.
Explanation:
One of the ways to address this issue is through the options given by the statement. The concepts related to the continuity equation and the Bernoulli equation.
Through these two equations it is possible to observe the behavior of the fluid, specifically the velocity at a constant height.
By definition the equation of continuity is,
[tex]A_1V_1=A_2V_2[/tex]
In the problem [tex]A_2[/tex] is [tex]2A_1[/tex], then
[tex]A_1V_1=2A_1V_2[/tex]
[tex]V_2 = \frac{V_1}{2}[/tex]
Here we can conclude that by means of the continuity when increasing the Area, a decrease will be obtained - in the diminished times in the area - in the speed.
For the particular case of Bernoulli we have to
[tex]P_1 + \frac{1}{2}\rho V_1^2 = P_2 +\frac{1}{2}\rho V_2^2[/tex]
[tex]P_2-P_1 = \frac{1}{2} \rho (V_1^2-V_2^2)[/tex]
For the previous definition we can now replace,
[tex]P_2-P_1 = \frac{1}{2} \rho (V_1^2-(\frac{V_1}{2})^2)[/tex]
[tex]\Delta P = \frac{3}{8} \rho V_1^2[/tex]
Expressed from Bernoulli's equation we can identify that the greater the change that exists in pressure, fluid velocity will tend to decrease
The correct answer is B: "If we increase A2 then by the continuity equation the speed of the fluid should decrease. Bernoulli's equation then shows that if the velocity of the fluid decreases (at constant height conditions) then the pressure of the fluid should increase"