Answer:
1.) [tex]-\frac{5}{2}[/tex]
2.) y = 2x - 1 is neither parallel nor perpendicular to line a.
y = - 2x + 5 is parallel to line a.
[tex]y = \frac{1}{2} x + 7[/tex] line is perpendicular to line a.
3.)2x + 5y = -10
Step-by-step explanation:
1.) Given straight line is 5y = 10 + 2x
⇒ [tex]y = \frac{2}{5} x + 2[/tex]
So, the slope of the given line is [tex]\frac{2}{5}[/tex]
Therefore, the slope of the straight line which is perpendicular to the above line will be [tex]-\frac{5}{2}[/tex]
{Since the product of slopes of two perpendicular straight line is -1}
2.) Line a is y = - 2x + 3
Now, y = 2x - 1 is neither parallel nor perpendicular to line a.
y = - 2x + 5 is parallel to line a.
And [tex]y = \frac{1}{2} x + 7[/tex] line is perpendicular to line a.
3.) The equation of the straight line which is parallel to line 2x + 5y = 10 will be 2x + 5y = c, where c is any constant.
If this parallel line passes through (5,-4), then c = 2(5) + 5(- 4) = -10
So the equation of the parallel line is 2x + 5y = -10 (Answer)