Respuesta :

nkirotedoreen46

Answer:

528.086 atm

Explanation:

We are given;

The number of moles of an ideal gas as 3.6 moles

Volume occupied by the gas is 150 mL or 0.15 L

Temperature of the gas is -5° C

But, K = °C + 273.15

Therefore, Temperature, T = 268.15 K

We are required to calculate the pressure in the tank.

In this case we are going to use the ideal gas equation;

  • The ideal gas equation states, PV = nRT, where P is the pressure, v is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant, 0.082057 L.atm/mol.K
  • Therefore, rearranging the equation we can find the pressure in the tank.

P = nRT÷ V

 = (3.6 mole × 0.082057 × 268.15 K)÷ 0.15 L

 =528.086 atm

Therefore, the pressure in the tank is 528.086 atm

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