Answer:
The rent of 1 chair is $1.5 and rent for 1 table is $8.25.
Explanation:
Given:
A party rental company has chairs and tables for rent.
Let the rent for a single chair be $m and rent for single table be $n.
The total cost to rent 8 chairs and 4 tables is $ 45 .
Then, 8 x $m + 4 x $n = $45 8m + 4n = 45 (1)
The total cost to rent 3 chairs and 2 tables is $ 21.
Then, 3 x $m + 2 x $n = $ 21 3m + 2n = 21 (2)
To find:
what is the cost to rent each chair and each table?
Solution:
let us solve the above two equations.
Equation(1) x 1 ........... 8m + 4n = 45
Equation(2) x 2.......... 6m + 4n = 42 [we multiplied with 2 because, then, coefficient of n equals and easy to cancel
8m + 4n = 45
6m + 4n = 42
(-)----------------------------
2m + 0 = 3
M = [tex]\frac{3}{2}[/tex] = 1.5
Then, substitute m = 1.5 in (1)
8(1.5) + 4n = 45
12 + 4n = 45
4n = 45 – 12
4n = 33
n = 8.25
Hence, the rent of 1 chair is $1.5 and rent for 1 table is $8.25.
