Answer:
8N is the net force on the object.
Explanation:
Given that,
[tex]\mathrm{F}_{\text {norm }}[/tex]=20N is normal force acting upward (+20N)
[tex]F_{\text {frict }}[/tex]=14N is frictional force which is opposite to the applied force (-14N)
[tex]\mathrm{F}_{\mathrm{app}}=[/tex]22N is applied force which is applied on right side (+22N)
[tex]\mathrm{F}_{\mathrm{grav}}[/tex]=20N is gravitational force acting downward (-20N)
We know that ,
[tex]\text { Fnet }[/tex]=applied force [tex]\left(\mathrm{F}_{\mathrm{app}}\right)[/tex]+frictional force[tex]\left(F_{\text {frict }}\right)[/tex]+normal force [tex]\left(\mathrm{F}_{\mathrm{norm}}\right)[/tex]+gravitational force [tex]\left(F_{\text {grav}}\right)[/tex]
[tex]\mathrm{F}_{\mathrm{net}}=[/tex]22+(-14)+ 20+(-20)
[tex]\mathrm{F}_{\mathrm{net}}=[/tex]22-14+20-20
[tex]\mathrm{F}_{\mathrm{net}}=8 \mathrm{N}[/tex]
Therefore the net force of the object be 8N.
