Answer:
x - 2y + 10 = 0
Step-by-step explanation:
The equation of parallel line differ only by their constant.
Hence, the equation of the line parallel to [tex]x - 2y - 6 = 0[/tex] is nothing but [tex]x - 2y + c = 0[/tex].
When a point passing through this line is given we can substitute the point in this line and get the value for [tex]c[/tex].
The line passes through [tex](-2, 4)[/tex].
Therefore, we have: [tex]-2 - 8 + c = 0 \implies c = 10[/tex]
Substituting this we get the equation of the parallel line as [tex]x - 2y + 10 = 0[/tex].
