Answer:
The velocities of each ball are
[tex]v_{f2}=8.08 m/s[/tex]
[tex]v_{f1}=5.28 m/s[/tex]
Explanation:
Using the conservation of momentum to find the velocity of each balls after the collision
[tex]m_1*v_1+m_2*v_2=m_1*v_{f1}+m_2*v_{f2}[/tex]
[tex]3kg*8m/s+2kg*4m/s=3kg*v_{f1}+2kg*v_{f2}[/tex]
[tex]32 kg*m/s=3kg*v_{f1}+2kg*v_{f2}[/tex]
Here have one equation but have two variable don't know so
[tex]e=\frac{v_{f2}-v_{f1}}{v_1-v_2}[/tex]
[tex]0.7=\frac{v_{f2}-v_{f1}}{8m/s-4m/s}[/tex]
[tex]v_{f2}-v_{f1}=2.8[/tex]
Now have two equations and two variables so solving using
[tex]v_{f2}=8.08 m/s[/tex]
[tex]v_{f1}=5.28 m/s[/tex]
