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A 1400 kg car is traveling on a level road at a constant speed of 26.8 m/s (60 miles per hour.) The drag force exerted by air on the car and the frictional force exerted by the road on the car’s tires add to give a net force of 680N pointing opposite to the direction of the car’s motion. What is the rate of work done (power) by the air and the road on the car

Respuesta :

Answer:

Power, P = 18224 watts

Explanation:

It is given that,

Mass of car, m = 1400 kg

Speed of the car, v = 26.8 m/s

The frictional force exerted by the road on the car’s tires, F = 680 N

We need to find the rate of doing work by the air and the road on the car. We know that rate of doing work is called power exerted. It is equal to the product of force and velocity. It is given by :

[tex]P=F\times v[/tex]

[tex]P=680\ N\times 26.8\ m/s[/tex]

P = 18224 watts

So, the power delivered by the air and the road on the car is 18224 watts. Hence, this is the required solution.

asuwafohjames

The rate of work done (power) by the air and the road on the car is 18224 W.

What is power?

Power is the rate at which work is done

To calculate the rate of work done (power) by the air and the road on the car, we use the formula below.

Formula:

  • P = V........... Equation 1

Where:

  • P = Power
  • F = Force
  • V = Velocity

From the question,

Given:

  • F = 680 N
  • V = 26.8 m/s

Substitute these values into equation 1

  • P = 680(26.8)
  • P = 18224 W

Hence, The rate of work done (power) by the air and the road on the car is 18224 W.

Learn more about power here: https://brainly.com/question/24858512

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