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Biologists have studied the running ability of the northern quoll, a marsupial indigenous to Australia. In one set of experiments, they studied the maximum speed that quolls could run around a curved path without slipping. One quoll was running at 2.6 m/s around a curve with a radius of 0.80 m when it started to slip. What was the coefficient of static friction between the quails feet and the ground in this trial?

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davidlcastiblanco

Answer:

[tex]u_K=0.862[/tex]

Explanation:

The force of friction between the quails feet and the ground is:

[tex]F=m*a[/tex]

[tex]F_K=m*a[/tex]

[tex]F_K=u_k*m*g[/tex]

[tex]u_K*m*g=m*a_c[/tex]

[tex]u_K*g=a[/tex]

[tex]u_K=\frac{a_c}{g}[/tex]

[tex]a_c=\frac{v^2}{r}[/tex]

So the coefficient of static is solve

[tex]u_K=\frac{\frac{v^2}{r}}{g}[/tex]

[tex]u_K=\frac{v^2}{r*g}=\frac{(2.6m/s)^2}{0.80m*9.8m/s^2}[/tex]

[tex]u_K=0.862[/tex]

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