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Answer:
There is a 99% probability that at least one of the intervals will cover the true mean yields at their location
Step-by-step explanation:
In a 90% confidence interval of the mean of a population, there is a 90% probability that it cover the true mean of the population.
What is the probability that at least one of the intervals will cover the true mean yields at their location?
This is 1 subtracted by the probability that none of them cover the true mean yields at their location.
For each one, there is a 10% probability that it does not cover the mean. So the probability that both do not cover the mean is [tex]0.1*0.1 = 0.01[/tex]
The probability that at least one of the intervals will cover the true mean yields at their location is 1-0.01 = 0.99 = 99%.
There is a 99% probability that at least one of the intervals will cover the true mean yields at their location.
Given
Researchers are studying the yield of a crop in two locations.
The researchers are going to compute independent 90% confidence intervals for the mean yield at each location.
What is independent probability?
\In Probability, the set of outcomes of an experiment is called events. There are different types of events such as independent events, dependent events, mutually exclusive events, and so on.
In a 90% confidence interval of the mean of a population, there is a 90% probability that it covers the true mean of the population.
Therefore,
The probability that at least one of the intervals will cover the true mean yields at their location is;
[tex]= 1-0.01\\\\=0.99\\\\= 0.99 \times 100\\\\\rm = 99 \ Percent[/tex]
Hence, tis a 99% probability that at least one of the intervals will cover the true mean yields at their location.
To know more about Independent probability click the link given below.
https://brainly.com/question/13628006
