A store sells both cold and hot beverages. Cold beverages, c, cost $1.50, while hot beverages, h, cost $2.00. On Saturday, drink receipts totaled $360, and 4 times as many cold beverages were sold as hot beverages.

Part 1: Write a system of equations to represent the beverage sales on Saturday.

Part 2: Use any solving method you like to solve the system of equations you wrote in Part 1. Show all of your work.

Question

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jitushashi143 jitushashi143 · Answer 1 · 2019-11-18T06:18:39+01:00

Answer:

The number of hot beverages sold were 45 and the number of cold beverages sold were 180.

Step-by-step explanation:

Let the number of cold beverages sold be [tex]c[/tex]

And the number of hot beverages sold be [tex]h[/tex]

According to the question:

c=4[tex]\times[/tex] h...

[tex]$[/tex] 1.5[tex]\times[/tex] c + 2[tex]\times[/tex] h = Sale of any day

Part1:

For Saturday.

The sale is of [tex]$[/tex]360

then

[tex]$[/tex] 1.5 [tex]\times[/tex] c + [tex]$[/tex] 2 [tex]\times[/tex] h =[tex]$[/tex] 360

Part 2:

Following the method of substitution.

And plugging the values of c=4[tex]\times[/tex] h...in equation where the sales of Saturday is given.

1.5[tex]\times[/tex] c + 2[tex] \times[/tex] h =360

1.5[tex]\times[/tex] 4[tex]\times[/tex] h + 2 [tex]\times[/tex] h =360

6[tex]\times[/tex] h + 2[tex]\times[/tex] h= 360

8[tex]\times[/tex] h=360

Dividing both sides with 8.

h=[tex]\frac{360}{8}[/tex]

h=45

Inserting h=45 in c=4 [tex]\times[/tex] h...

we have c=4[tex]\times[/tex] 45 = 180

So the number of hot beverages sold were 45 and the number of cold beverages sold were 180.