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A 282 kg bumper car moving right at 3.50 m/s collides with a 155 kg bumper car moving 1.8 m/s left. Afterwards, the 282 kg car moves right at 0.800 m/s. What is the momentum of the 155 kg car afterwards? (Unit=kg*m/s)

Respuesta :

bacon371

Answer:

482.4kgm/s

Explanation:

...482.4kgm/s

MathPhys

Answer:

482 kg m/s

Explanation:

Momentum before = momentum after

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(282)(3.50) + (155)(-1.80) = (282)(0.800) + (155) v

987 − 279 = 225.6 + 155v

v = 3.11 m/s

The momentum of the car is:

p = mv

p = (155 kg) (3.11 m/s)

p = 482 kg m/s

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