Answer:
Horizontal component of velocity =1.7364m/s
Vertical component of velocity =9.848m/s
Explanation:
As the ball is a 2D projectile,it has two components.
Concept of components of a vector:
1)All the possible independent components of a vector sum up to give the vector.
2)If the magnitude of a vector is v,then its component in the direction at an angle of Θ from the vector is equal to - vcos(Θ).
Now as the ball is having 2D motion,it has two independent components one along the horizontal,one along the vertical.
Given angle of velocity with horizontal [tex]\alpha[/tex]=[tex]80[/tex]°
Therefore angle of velocity with vertical [tex]\beta = 90[/tex]°[tex]-80[/tex]°
[tex]\beta =10[/tex]°
Therefore,
Component of Velocity along horizontal = [tex]vcos(\alpha )[/tex]
[tex]v_{x}=10\times[/tex]cos(80°)
[tex]1.7364m/s[/tex]
Component of velocity along vertical = [tex]vsin(\beta )[/tex]
[tex]v_{y}=10\times[/tex]cos(10°)
[tex]v_{y}= 9.848m/s[/tex]
Therefore
Horizontal component of velocity of ball[tex]v_{x}[/tex] =1.7364m/s
Vertical component of velocity of ball[tex]v_{y}[/tex] =9.848m/s
