104.16 g of oxygen (O₂)
Explanation:
We have the following chemical reaction:
C₂H₆ (I) + 7/2 O₂ (g) = 2 CO₂ (g) + 3 H₂O (I)
we multiply the reaction by 2 in order to have integer coefficients
2 C₂H₆ (I) + 7 O₂ (g) = 4 CO₂ (g) + 6 H₂O (I)
To calculate the number of moles of water (H₂O) we use the Avogadro's number:
if 1 mole of H₂O contains 6.022 × 10²³ molecules of H₂O
then X moles of H₂O contains 1.68 × 10²⁴ molecules of H₂O
X = (1.68 × 10²⁴ × 1) / 6.022 × 10²³ = 0.279 × 10 = 2.79 moles of H₂O
Now taking in account the chemical reaction, we devise the following reasoning:
if 7 moles of O₂ produces 6 moles of H₂O
then X moles of O₂ produces 2.79 moles of H₂O
X = (7 × 2.79) / 6 = 3.255 moles of O₂
mass = number of moles × molecular weight
mass of O₂ = 3.255 × 32 = 104.16 g
Learn more about:
Avogadro's number
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