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The bond length in the HBr molecule is 1.41 Å. Calculate the dipole moments, in debyes, if the charges on the H and Br atoms were +1 and -1, respectively.

Respuesta :

Answer:

The Dipole moment is 6.77 Debyes.

Explanation:

Given bond length of HBr molecule = 1.41 A°,

We also know charges on H and Br(+1 and -1 respectively)

Charge on H  =  (+1) [tex]\times[/tex] (absolute charge of electron);

Charge on Br  =  (-1) [tex]\times[/tex] (absolute charge of electron);

Since absolute charge on electron = [tex]1.602\times 10^{-19}[/tex];

Therefore charge on H = [tex]1.602\times 10^{-19}[/tex] Coulomb;

charge on Br = [tex]-1.602\times10^{-19}[/tex]

We know Dipole Moment = Charge [tex]\times[/tex] Distance;

Here,

Distance = Bond Length = 1.41 A° = 1.41 [tex]\times 10^{-10}[/tex];

and charge on atom =  [tex]1.602\times 10^{-19}[/tex] Coulomb;

Therefore,

Dipole Moment =  Distance [tex]\times[/tex] Charge

Dipole Moment =  [tex]1.41\times10^{-10} \times1.602\times10^{-19}[/tex];

Dipole Moment =  [tex]2.25882\times10^{-29}[/tex] SI units.

The conversion factor of for SI units to Debye is 2.9989 [tex]\times 10^{29}[/tex]

Therefore,

Dipole Moment = 2.25882 [tex]\times 10^{-29}\times 2.9985\times10^{29}[/tex]

Dipole Moment = 6.77 Debye.