Answer:
maximum possible potential difference = 1.62 mV
Explanation:
given data
diameter d = 0.75 cm = 0.75 × [tex]10^{-2}[/tex] m
flow speed v = 0.9 m/s
magnetic field B = 0.24 T
to find out
maximum possible potential difference across the diameter
solution
we know that maximum possible potential difference formula is
Vh = Vd× B × d .............................1
put here value in equation 1 we get
maximum possible potential difference = 0.9 × 0.24 × 0.75 × [tex]10^{-2}[/tex]
solve we get
maximum possible potential difference = 1.62 × [tex]10^{-3}[/tex]
maximum possible potential difference = 1.62 mV
The maximum possible potential difference across the diameter of the artery?is mathematically given as
vh= 1.62 mV
Question Parameter(s):
A large artery with a diameter of 0.75 cm
a flow speed of 0.9 m/s.
If a section of this artery is in a magnetic field of 0.24 T,
Generally, the equation for the potential difference is mathematically given as
Vh = Vd× B × d
Therefore
vh= 0.9 * 0.24 * 0.75 × 10^{-2}
vh= 1.62 mV
In conclusion, potential difference
vh= 1.62 mV
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