Answer:
[tex]q=390.285x10^{-12}C[/tex]
Explanation:
Those kind of problems of electric physics is about capacitors, so the normal questions are:
What are the charge on each electrode?
Solve this you can get other information required in the problem or write down the other questions you need
[tex]7.0cm*\frac{1m}{100cm}=70x10^{-3}m[/tex]
[tex]A=70x10^{-3}m*70x10^{-3}m=4.9x10^{-3}m62[/tex]
Capacitance
[tex]C=E_o*\frac{A}{d}[/tex]
[tex]E_o=8.85x10^{-12}\frac{C^2}{N*m^2}[/tex]
[tex]C=8.85x10^{-12}\frac{C^2}{N*m^2}*\frac{4.9x10^{-3}m^2}{1x10^{-3}m}[/tex]
[tex]C=43.365x10^{-12}F[/tex]
[tex]C=43.365pF[/tex]
The charge is find by the equation
[tex]q=C*V[/tex]
[tex]q=43.365pF*9V[/tex]
[tex]q=390.285x10^{-12}C[/tex]
