Answer:A, I. Mean X=8.8+3.1+4.2+6.2+7.6+3.6/6=5.58.
ii. S.D. for ungrouped data is given as √E[x-X]²/√6
[x-X] ²= 8.8-5.58+3.1-5.58+4.2-5.58+6.2-5.58+7.6-5.58+3.6-5.58=0.02² S.D=√0.02²/√6.
=0.02/2.449=0.00816.
iii. Standard error of the mean =
S.D./√N = 0.00816/6=0.00136.
B. If additional six measurements
were added to the previous one:
I. Mean X= adding total 12 samples and divide by 12 gives 5.51.
ii. Sample S.D. for all the 12 experiment by following same step in A for the 12 experiment gives 0.02/√12 =0.02/3.46=0.0057
iii. Standard error of the mean for the 12 experiment is S.D./√N= 0.0057/12=0.00048.
Explanation: