Answer:
3000 hours is 0.2618 standard deviations above the mean.
Step-by-step explanation:
In this problem, we have that:
The mean of C was found to be found to be 2,154 hours and the variance of C was found to be 10,440,820.
How many standard deviations above the mean is 3,000 hours?
The first step to solve this problem is finding the standard deviation of C.
This is the square root of the variance of C.
We have that the variance of C is 10,440,820. So
[tex]\sigma = \sqrt{10440820} = 3231.22[/tex]
Now, the number of standard deviation abve the mean of 3000 ours is given by:
[tex]Z = \frac{3000 - 2154}{3231.22} = 0.2618[/tex]
3000 hours is 0.2618 standard deviations above the mean.
