contestada

1. The area of a square with side length x, where the side length is decreased by 3, the area is
multiplied by 2 and then 4 square units are added to the area.​

Respuesta :

Answer:

[tex]2x^2-12x+22[/tex]

Step-by-step explanation:

Let's follow what the problem asks us:

  • "The area of a square with side length x"

this is the formula for area: [tex]area=side*side=side^2[/tex]

since the side length is x, the initial area is: [tex]x^2[/tex]

  • Now, "where the side length is decreased by 3":

The side is now [tex](x-3)[/tex], thus the area is: [tex](x-3)^2=x^2-6x+9[/tex]

  • "the area is multiplied by 2"

we had the area [tex]x^2-6x+9[/tex], when we multiply by 2:

[tex](2)(x^2-6x+9)=2x^2-12x+18[/tex]

  • And finally " then 4 square units are added to the area.​"

this is: [tex]2x^2-12x+18 + 4=2x^2-12x+22[/tex]

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