Answer:
Option C
The angular acceleration of flywheel A is smaller than flywheel B.
Explanation:
Flywheel B
T = mgr where m is mass, g is acceleration due to gravity, r is the radius
[tex]0.5 mr^{2}\times a_B=mgr[/tex]
[tex]a_B= \frac {2g}{r}[/tex] where [tex]a_B[/tex] is angular acceleration of Flywheel B
Flywheel A
[tex]mr^{2}\times a_A= mgr[/tex]
[tex]a_A=\frac {g}{r}[/tex] where [tex]a_A[/tex] is angular acceleration of Flywheel A
so, [tex]a_A<a_B[/tex]
Therefore, the angular acceleration of flywheel A is smaller than flywheel B.